So that is the next step, we have our data table

now I need to set up our k expression.

So k is going to equal to NO squared because I have NO as a product. now I need to set up our k expression.

So k is going to equal to NO squared because I have NO as a product.

2 is the coefficient of it, so that becomes the power.

N_2 is an reactant 2 is the coefficient of it, so that becomes the power.

N_2 is an reactant

and O_2 is a reactant so they both go into the denominator.

They both have coefficients of 1

so I do not have any powers associated with them.

Now, I have k equals NO squared

over N_2 times O_2

I can plug in the values I know over N_2 times O_2

I can plug in the values I know

and I find that I get 4.10 x 10 ^ -4

equals 2x squared

because I had 2x in my equilibrium row

I still have to remember to square that

because 2x represents the concentration.

The square is part of the law of mass action.

On the bottom, I have 0.250 - x The square is part of the law of mass action.

On the bottom, I have 0.250 - x

and 0.430 - x.

Now if I were to solve this

and rearrange to solve time for x

what I am going to find, is that I have a quadratic equation.

This makes the calculation a little more complicated. what I am going to find, is that I have a quadratic equation.

This makes the calculation a little more complicated.

However, in some cases

we can make a simplifying assumption.