Now what I want to do is write the transfer function for

this cascade in standard form of a second-order filter, and

you can see that when we multiply these two transfer functions out, we're

going to have a second-order denominator, an S squared term in the denominator.

So by mani, manipulating this and

putting it into standard form for a second-order filter, remember.

For a second-order filter, we can write the denominator like this.

S over omega naught squared, plus one over q, s over omega naught plus one.

Some gang constant K out front, and

then the numerator is composed of one of the terms of the denominator, or

some combination of these terms [NOISE]

So, let, let me just multiply out this transfer function.

So, I can write that Vo over Vi is equal to K1.

K 2 [NOISE] and the numerator we still have our S over omega L.